4.9x^2+16x-2.1=0

Solution for 4.9x^2+16x-2.1=0 equation:

4.9x^2+16x-2.1=0

a = 4.9; b = 16; c = -2.1;
Δ = b2-4ac
Δ = 162-4·4.9·(-2.1)
Δ = 297.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-\sqrt{297.16}}{2*4.9}=\frac{-16-\sqrt{297.16}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+\sqrt{297.16}}{2*4.9}=\frac{-16+\sqrt{297.16}}{9.8}
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